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On power values of sum of divisors function in arithmetic progressions

Author

Listed:
  • Sai Teja Somu

    (JustAnswer)

  • Vidyanshu Mishra

    (Delhi Technological University)

Abstract

Let $$a\ge 1, b\ge 0$$ a ≥ 1 , b ≥ 0 and $$k\ge 2$$ k ≥ 2 be any given integers. It has been proven that there exist infinitely many natural numbers m such that sum of divisors of m is a perfect kth power. We try to generalize this result when the values of m belong to any given infinite arithmetic progression $$an+b$$ a n + b . We prove if a is relatively prime to b and order of b modulo a is relatively prime to k then there exist infinitely many natural numbers n such that sum of divisors of $$an+b$$ a n + b is a perfect kth power. We also prove that, in general, either sum of divisors of $$an+b$$ a n + b is not a perfect kth power for any natural number n or sum of divisors of $$an+b$$ a n + b is a perfect kth power for infinitely many natural numbers n.

Suggested Citation

  • Sai Teja Somu & Vidyanshu Mishra, 2024. "On power values of sum of divisors function in arithmetic progressions," Indian Journal of Pure and Applied Mathematics, Springer, vol. 55(1), pages 335-340, March.
  • Handle: RePEc:spr:indpam:v:55:y:2024:i:1:d:10.1007_s13226-023-00367-5
    DOI: 10.1007/s13226-023-00367-5
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